47 lines
1.4 KiB
SQL
47 lines
1.4 KiB
SQL
--- It wil find the indexes present on a table 'test'
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postgres=# select * from pg_indexes where tablename='test';
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schemaname | tablename | indexname | tablespace | indexdef
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------------+-----------+-----------+-------------+----------------------------------------------------------
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public. | test | tes_idx1 | ts_postgres | CREATE INDEX tes_idx1 ON public.test USING btree (datid)
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(1 row)
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-- All indexes present in database:
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postgres#select * from pg_indexes
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-- It will show all index details including size:
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postgres=# \di+
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List of relations
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Schema | Name | Type | Owner | Table | Size | Description
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--------+----------+-------+----------+--------+--------+-------------
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public | tes_idx | index | postgres | test56 | 64 kB |
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public | tes_idx1 | index | postgres | test | 472 MB |
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(2 rows)
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-- Find indexes with respective column name for table( here table name is test)
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REFERENCE - https://stackoverflow.com/questions/2204058/list-columns-with-indexes-in-postgresql
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select
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t.relname as table_name,
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i.relname as index_name,
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array_to_string(array_agg(a.attname), ', ') as column_names
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from
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pg_class t,
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pg_class i,
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pg_index ix,
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pg_attribute a
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where
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t.oid = ix.indrelid
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and i.oid = ix.indexrelid
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and a.attrelid = t.oid
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and a.attnum = ANY(ix.indkey)
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and t.relkind = 'r'
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and t.relname ='test'
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group by
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t.relname,
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i.relname
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order by
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t.relname,
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i.relname; |